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  <channel>
    <title>Çemberde Açı-Uzunluk ve Dairenin Alanı</title>
    <description>Çemberde Açı-Uzunluk ve Dairenin Alanı</description>
    <pubDate>Fri, 09 Oct 2026 01:08:37 +0000</pubDate>
    <lastBuildDate>Fri, 09 Oct 2026 01:08:37 +0000</lastBuildDate>
    <generator>SorumVar.Net</generator>
    <link>https://www.sorumvar.net/frm/konu/cemberde-aci-uzunluk-ve-dairenin-alani.26/</link>
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    <item>
      <title>Thales ve Pisagor Teoremleri - Çarpanlara Ayırma - Çemberin Analitiği</title>
      <pubDate>Thu, 01 Oct 2026 11:11:42 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/thales-ve-pisagor-teoremleri-carpanlara-ayirma-cemberin-analitigi.15835/</link>
      <guid>https://www.sorumvar.net/frm/konular/thales-ve-pisagor-teoremleri-carpanlara-ayirma-cemberin-analitigi.15835/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<a href="https://servimg.com/view/19971039/5571" target="_blank" class="externalLink" rel="nofollow"><img src="https://i72.servimg.com/u/f72/19/97/10/39/zembe108.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /></a><br />
<a href="https://i72.servimg.com/u/f72/19/97/10/39/zembe108.png" target="_blank" class="externalLink" rel="nofollow">https://i72.servimg.com/u/f72/19/97/10/39/zembe108.png</a><br />
<a href="https://drive.google.com/uc?export=download&amp;id=1ne5rVJYf5uw2v2AP2-cNg2NdkF3YDWdb" target="_blank" class="externalLink" rel="nofollow">https://drive.google.com/uc?export=download&amp;id=1ne5rVJYf5uw2v2AP2-cNg2NdkF3YDWdb</a><br />
(Sayfa 44, Soru 40, Yanıtlar son sayfada)<br />
<br />
M1 Merkezli çemberin yarıçapı = 6 birim<br />
M3 Merkezli çemberin yarıçapı = 3·6 = 18 birim <br />
M3 Merkezli çemberin merkezinin ordinatı: 18<br />
|AO| = |AB| = a birim<br />
O-M1-M2: Doğrusal<br />
M2...<br />
<br />
<a href="https://www.sorumvar.net/frm/konular/thales-ve-pisagor-teoremleri-carpanlara-ayirma-cemberin-analitigi.15835/" class="internalLink">Thales ve Pisagor Teoremleri - Çarpanlara Ayırma - Çemberin Analitiği</a>]]></content:encoded>
    </item>
    <item>
      <title>Çemberlerde Benzerlik ve Çevre - Kürede Yüzey Alanı</title>
      <pubDate>Tue, 29 Sep 2026 12:06:42 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/cemberlerde-benzerlik-ve-cevre-kurede-yuzey-alani.15828/</link>
      <guid>https://www.sorumvar.net/frm/konular/cemberlerde-benzerlik-ve-cevre-kurede-yuzey-alani.15828/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<img src="https://i.ibb.co/qMmBSXPw/ember-K-re.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /><br />
<a href="https://i.ibb.co/qMmBSXPw/ember-K-re.png" target="_blank" class="externalLink" rel="nofollow">https://i.ibb.co/qMmBSXPw/ember-K-re.png</a><br />
<a href="https://drive.google.com/uc?export=download&amp;id=1Y2idlkBFRJZId_O9-F3dT-6oICe8Kxop" target="_blank" class="externalLink" rel="nofollow">https://drive.google.com/uc?export=download&amp;id=1Y2idlkBFRJZId_O9-F3dT-6oICe8Kxop</a><br />
(Sayfa 40, Soru 40, Yanıtlar son sayfada)<br />
<br />
Küre biçimli gök cisminin yarıçapı: r km<br />
Uydunun çembersel yörüngesinin uzunluğu yani çevresi: [ 500<span style="font-family: 'Times New Roman'"><span style="font-size: 18px">π</span></span> km / (60 dakika) ]·90 dakika = 750<span style="font-family: 'Times New Roman'"><span style="font-size: 18px">π</span></span> km<br />
<b><span style="color: #b300b3">Tüm çemberler...</span></b><br />
<br />
<a href="https://www.sorumvar.net/frm/konular/cemberlerde-benzerlik-ve-cevre-kurede-yuzey-alani.15828/" class="internalLink">Çemberlerde Benzerlik ve Çevre - Kürede Yüzey Alanı</a>]]></content:encoded>
    </item>
    <item>
      <title>Çeyrek Dairelerin Kesişiminde Simetri - Çemberin Analitiği (Bu çözüm Google Gemini'ye KAPAK olsun!)</title>
      <pubDate>Sun, 20 Sep 2026 12:45:04 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/ceyrek-dairelerin-kesisiminde-simetri-cemberin-analitigi-bu-cozum-google-geminiye-kapak-olsun.15796/</link>
      <guid>https://www.sorumvar.net/frm/konular/ceyrek-dairelerin-kesisiminde-simetri-cemberin-analitigi-bu-cozum-google-geminiye-kapak-olsun.15796/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<img src="https://i.ibb.co/rN8Z82f/question.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /><br />
<a href="https://i.ibb.co/rN8Z82f/question.png" target="_blank" class="externalLink" rel="nofollow">https://i.ibb.co/rN8Z82f/question.png</a><br />
<a href="https://drive.google.com/uc?export=download&amp;id=1pHvlN-p-v3VLg-fM42v5-IQIhmw5p73r" target="_blank" class="externalLink" rel="nofollow">https://drive.google.com/uc?export=download&amp;id=1pHvlN-p-v3VLg-fM42v5-IQIhmw5p73r</a><br />
(Sayfa 40, Soru 40, Yanıtlar son sayfada)<br />
<br />
Aslında Şekil - 3 hatalı çizilmiş çünkü 1 + 1 = 2 birim uzunluğundaki çubuk saat yönünde gidebilmek için (2, 0) noktası etrafında 90 derece ve x ekseninin pozitif yönünde dönüp x ekseninin üzerinde kalarak x = 2 doğrusu haline geliyor.<br />
<br />
<i><span style="text-decoration: underline">Grafik:</span>...</i><br />
<br />
<a href="https://www.sorumvar.net/frm/konular/ceyrek-dairelerin-kesisiminde-simetri-cemberin-analitigi-bu-cozum-google-geminiye-kapak-olsun.15796/" class="internalLink">Çeyrek Dairelerin Kesişiminde Simetri - Çemberin Analitiği (Bu çözüm Google Gemini&#039;ye KAPAK olsun!)</a>]]></content:encoded>
    </item>
    <item>
      <title>Çemberin Analitiği - Pisagor Teoremi - Dairede ve Karede Alan - İntegral</title>
      <pubDate>Sat, 01 Aug 2026 20:45:04 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/cemberin-analitigi-pisagor-teoremi-dairede-ve-karede-alan-integral.15669/</link>
      <guid>https://www.sorumvar.net/frm/konular/cemberin-analitigi-pisagor-teoremi-dairede-ve-karede-alan-integral.15669/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[Çözümlü SAT hazırlık sorularından birinin fen lisesi için klasik sınav uyarlaması:<br />
<br />
<img src="https://i.ibb.co/CsPf1L0F/SAT-Question.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /><br />
<a href="https://i.ibb.co/CsPf1L0F/SAT-Question.png" target="_blank" class="externalLink" rel="nofollow">https://i.ibb.co/CsPf1L0F/SAT-Question.png</a><br />
<br />
<i><span style="font-size: 18px"><span style="color: #660000">Yukarıdaki problemin çözümünü geometrik olarak yapınız ve aynı sonucu vermek üzere içinde integral de bulunan işlemi yalnızca yazınız.</span></span></i><br />
<br />
<span style="text-decoration: underline"><i>Geometrik Çözüm:</i></span><br />
<img src="https://i.ibb.co/N6L7QbHn/SAT-Video.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" />...<br />
<br />
<a href="https://www.sorumvar.net/frm/konular/cemberin-analitigi-pisagor-teoremi-dairede-ve-karede-alan-integral.15669/" class="internalLink">Çemberin Analitiği - Pisagor Teoremi - Dairede ve Karede Alan - İntegral</a>]]></content:encoded>
    </item>
    <item>
      <title>Circle Equation - Integral</title>
      <pubDate>Wed, 29 Jul 2026 15:17:32 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/circle-equation-integral.15658/</link>
      <guid>https://www.sorumvar.net/frm/konular/circle-equation-integral.15658/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[The changed and slightly challenged version of an extremely easy question:<br />
<br />
<i><span style="font-size: 18px"><span style="color: #660000">By integrating, compute the area of the region bounded by the circle that is tangent to both axes with a radius of 6 units and the coordinate axes in the third quadrant.</span></span></i><br />
<br />
From the equation in the question [ x - (-6) ]^2 + [ y - (-6) ]^2 = 6^2 ⇒ y = f(x) = ( 36 - (x + 6)^2 )^0,5 - 6<br />
Area = (lower bound x = -6, upper bound x = 0), ∫ ( 0 - ( ( 36 - (x + 6)^2 )^0,5 - 6 ) ) dx...<br />
<br />
<a href="https://www.sorumvar.net/frm/konular/circle-equation-integral.15658/" class="internalLink">Circle Equation - Integral</a>]]></content:encoded>
    </item>
    <item>
      <title>Çemberin Analitiği - Dairesel Alanlar Arası Fark - İntegral</title>
      <pubDate>Wed, 29 Jul 2026 12:10:27 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/cemberin-analitigi-dairesel-alanlar-arasi-fark-integral.15657/</link>
      <guid>https://www.sorumvar.net/frm/konular/cemberin-analitigi-dairesel-alanlar-arasi-fark-integral.15657/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<img src="https://i.ibb.co/N69z2TQG/ember.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /><br />
<a href="https://i.ibb.co/N69z2TQG/ember.png" target="_blank" class="externalLink" rel="nofollow">https://i.ibb.co/N69z2TQG/ember.png</a><br />
<a href="https://www.facebook.com/photo/?fbid=28750667181189659&amp;set=gm.27611570248535762&amp;idorvanity=6759845047468253" target="_blank" class="externalLink" rel="nofollow">https://www.facebook.com/photo/?fbi...27611570248535762&amp;idorvanity=6759845047468253</a><br />
<br />
<span style="text-decoration: underline"><i>Geometrik Çözüm:</i></span><br />
4·( <span style="font-family: 'Times New Roman'"><span style="font-size: 18px">π</span></span>·4^2 / 4 - ( <span style="font-family: 'Times New Roman'"><span style="font-size: 18px">π</span></span>·4^2·60° / 360° + ( <span style="font-family: 'Times New Roman'"><span style="font-size: 18px">π</span></span>·4^2·60° / 360° - (1 / 2)·4^2·sin(60°) ) ) ) = <span style="color: #0000b3">16·[ √3 -...</span><br />
<br />
<a href="https://www.sorumvar.net/frm/konular/cemberin-analitigi-dairesel-alanlar-arasi-fark-integral.15657/" class="internalLink">Çemberin Analitiği - Dairesel Alanlar Arası Fark - İntegral</a>]]></content:encoded>
    </item>
    <item>
      <title>Çemberde Aynı Yayı Gören Çevre Açılar - Üçgende Alanın Trigonometrik Hesabı - Pisagor Teoremi</title>
      <pubDate>Sun, 24 May 2026 18:59:10 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/cemberde-ayni-yayi-goren-cevre-acilar-ucgende-alanin-trigonometrik-hesabi-pisagor-teoremi.15508/</link>
      <guid>https://www.sorumvar.net/frm/konular/cemberde-ayni-yayi-goren-cevre-acilar-ucgende-alanin-trigonometrik-hesabi-pisagor-teoremi.15508/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<a href="https://servimg.com/view/19971039/5393" target="_blank" class="externalLink" rel="nofollow"><img src="https://i72.servimg.com/u/f72/19/97/10/39/questi10.jpg" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /></a><br />
<a href="https://i72.servimg.com/u/f72/19/97/10/39/questi10.jpg" target="_blank" class="externalLink" rel="nofollow">https://i72.servimg.com/u/f72/19/97/10/39/questi10.jpg</a><br />
<a href="https://www.facebook.com/photo/?fbid=26993035163670666&amp;set=gm.2752802028431626&amp;idorvanity=289690338076153" target="_blank" class="externalLink" rel="nofollow">https://www.facebook.com/photo/?fbi...m.2752802028431626&amp;idorvanity=289690338076153</a><br />
<br />
<a href="https://servimg.com/view/19971039/5392" target="_blank" class="externalLink" rel="nofollow"><img src="https://i72.servimg.com/u/f72/19/97/10/39/zembe107.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /></a><br />
<a href="https://i72.servimg.com/u/f72/19/97/10/39/zembe107.png" target="_blank" class="externalLink" rel="nofollow">https://i72.servimg.com/u/f72/19/97/10/39/zembe107.png</a><br />
<br />
θ = arccos(4 /...<br />
<br />
<a href="https://www.sorumvar.net/frm/konular/cemberde-ayni-yayi-goren-cevre-acilar-ucgende-alanin-trigonometrik-hesabi-pisagor-teoremi.15508/" class="internalLink">Çemberde Aynı Yayı Gören Çevre Açılar - Üçgende Alanın Trigonometrik Hesabı - Pisagor Teoremi</a>]]></content:encoded>
    </item>
    <item>
      <title>Dairede Alan - Trigonometri</title>
      <pubDate>Fri, 09 Jan 2026 15:39:26 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/dairede-alan-trigonometri.15203/</link>
      <guid>https://www.sorumvar.net/frm/konular/dairede-alan-trigonometri.15203/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<img src="https://i.ibb.co/Hp2ZHNyq/daire.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /><br />
<a href="https://i.ibb.co/Hp2ZHNyq/daire.png" target="_blank" class="externalLink" rel="nofollow">https://i.ibb.co/Hp2ZHNyq/daire.png</a><br />
<a href="https://drive.google.com/drive/folders/1tO9jw6JSCP0II5u6BNdWrmXpZW272Czh" target="_blank" class="externalLink" rel="nofollow">https://drive.google.com/drive/folders/1tO9jw6JSCP0II5u6BNdWrmXpZW272Czh</a><br />
(Son soru, yanıtlar yok)<br />
<br />
G noktası [AF[ üzerinde olmak üzere |AG| en büyük dairenin yarıçapı olmak üzere;<br />
|AB| = p birim<br />
|BF| = q birim<br />
|FG| = r birim<br />
Pembe Alan = <span style="font-family: 'Times New Roman'"><span style="font-size: 18px">π</span></span>·(p + q)^2 / 4 - <span style="font-family: 'Times New Roman'"><span style="font-size: 18px">π</span></span>·p^2 / 4<br />
Mavi Alan = [FONT=Times New...<br />
<br />
[url=&#039;https://www.sorumvar.net/frm/konular/dairede-alan-trigonometri.15203/&#039;]Dairede Alan - Trigonometri[/url]]]></content:encoded>
    </item>
    <item>
      <title>Çemberde Uzunluk - Analitik Geometri</title>
      <pubDate>Tue, 23 Sep 2025 07:45:34 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/cemberde-uzunluk-analitik-geometri.7531/</link>
      <guid>https://www.sorumvar.net/frm/konular/cemberde-uzunluk-analitik-geometri.7531/</guid>
      <author>Bora.</author>
      <dc:creator>Bora.</dc:creator>
      <content:encoded><![CDATA[Kolay gelsin

	<a href="http://www.sorumvar.net/frm/attachments/1479/" target="_blank">Eki Görüntüle 1479</a>]]></content:encoded>
      <slash:comments>2</slash:comments>
    </item>
    <item>
      <title>Daire Alanı - İntegral</title>
      <pubDate>Fri, 12 Sep 2025 08:35:44 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/daire-alani-integral.14890/</link>
      <guid>https://www.sorumvar.net/frm/konular/daire-alani-integral.14890/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<a href="https://servimg.com/view/19971039/4968" target="_blank" class="externalLink" rel="nofollow"><img src="https://i72.servimg.com/u/f72/19/97/10/39/daire16.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /></a><br />
<a href="https://i72.servimg.com/u/f72/19/97/10/39/daire16.png" target="_blank" class="externalLink" rel="nofollow">https://i72.servimg.com/u/f72/19/97/10/39/daire16.png</a><br />
<a href="https://drive.google.com/file/d/1laSDyQuFfyt8pqZ-mbsrfUnApcWYiw-m/view" target="_blank" class="externalLink" rel="nofollow">https://drive.google.com/file/d/1laSDyQuFfyt8pqZ-mbsrfUnApcWYiw-m/view</a><br />
[Sayfa 12 (pdf dosyada 10), Soru 37]<br />
<br />
<span style="text-decoration: underline"><i>Geometrik Çözüm:</i></span><br />
S: Eşit Alanlar<br />
<a href="https://servimg.com/view/19971039/4967" target="_blank" class="externalLink" rel="nofollow"><img src="https://i72.servimg.com/u/f72/19/97/10/39/daire_15.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /></a>...<br />
<br />
<a href="https://www.sorumvar.net/frm/konular/daire-alani-integral.14890/" class="internalLink">Daire Alanı - İntegral</a>]]></content:encoded>
    </item>
    <item>
      <title>Çemberde Uzunluk - Trigonometri - Pisagor Teoremi</title>
      <pubDate>Tue, 17 Jun 2025 07:59:36 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/cemberde-uzunluk-trigonometri-pisagor-teoremi.14741/</link>
      <guid>https://www.sorumvar.net/frm/konular/cemberde-uzunluk-trigonometri-pisagor-teoremi.14741/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<a href="https://servimg.com/view/19971039/4840" target="_blank" class="externalLink" rel="nofollow"><img src="https://i72.servimg.com/u/f72/19/97/10/39/zembe102.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /></a><br />
<a href="https://i72.servimg.com/u/f72/19/97/10/39/zembe102.png" target="_blank" class="externalLink" rel="nofollow">https://i72.servimg.com/u/f72/19/97/10/39/zembe102.png</a><br />
<a href="https://www.facebook.com/photo/?fbid=2128703480963185&amp;set=gm.2441142002930965&amp;idorvanity=289690338076153" target="_blank" class="externalLink" rel="nofollow">https://www.facebook.com/photo/?fbi...m.2441142002930965&amp;idorvanity=289690338076153</a><br />
<a href="https://www.facebook.com/photo.php?fbid=9919781781480935&amp;set=p.9919781781480935&amp;type=3" target="_blank" class="externalLink" rel="nofollow">https://www.facebook.com/photo.php?fbid=9919781781480935&amp;set=p.9919781781480935&amp;type=3</a> (<i>Benzerliği varsayım derecesinde uygulayarak yapılmış ve |CP| = 4 cm eşitliği ispatlanmadan...</i><br />
<br />
<a href="https://www.sorumvar.net/frm/konular/cemberde-uzunluk-trigonometri-pisagor-teoremi.14741/" class="internalLink">Çemberde Uzunluk - Trigonometri - Pisagor Teoremi</a>]]></content:encoded>
    </item>
    <item>
      <title>Paralelkenarda, Eşkenar Dörtgende ve Dairede Alan</title>
      <pubDate>Fri, 18 Apr 2025 16:00:53 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/paralelkenarda-eskenar-dortgende-ve-dairede-alan.14626/</link>
      <guid>https://www.sorumvar.net/frm/konular/paralelkenarda-eskenar-dortgende-ve-dairede-alan.14626/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<img src="https://i.ibb.co/HftqCzPx/paralelkenar.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /><br />
<a href="https://i.ibb.co/HftqCzPx/paralelkenar.png" target="_blank" class="externalLink" rel="nofollow">https://i.ibb.co/HftqCzPx/paralelkenar.png</a><br />
Dream Team Geometri 24-Dairenin Alanı<br />
<a href="https://z-library.sk/book/6101919/4ce7be/dream-team-geometri-24dairenin-alan%C4%B1.html" target="_blank" class="externalLink" rel="nofollow">https://z-library.sk/book/6101919/4ce7be/dream-team-geometri-24dairenin-alanı.html</a><br />
(Son soru yanıtlar yok)<br />
<br />
Çemberin Merkezi: O<br />
|CE| = |DE| = 12 / 2 = 6 birim = |CO| = |EO|<br />
∡BOC = ∡COE = ∡AOE = 180° / 3 = 60°<br />
E&#039;den [AB]&#039;ye inilen yüksekliğin [AB]&#039;yi...<br />
<br />
<a href="https://www.sorumvar.net/frm/konular/paralelkenarda-eskenar-dortgende-ve-dairede-alan.14626/" class="internalLink">Paralelkenarda, Eşkenar Dörtgende ve Dairede Alan</a>]]></content:encoded>
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    <item>
      <title>Çemberde ve Üçgende Açı</title>
      <pubDate>Fri, 11 Apr 2025 09:53:22 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/cemberde-ve-ucgende-aci.14609/</link>
      <guid>https://www.sorumvar.net/frm/konular/cemberde-ve-ucgende-aci.14609/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<img src="https://i.ibb.co/9mxfdw9g/ember.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /><br />
<a href="https://i.ibb.co/9mxfdw9g/ember.png" target="_blank" class="externalLink" rel="nofollow">https://i.ibb.co/9mxfdw9g/ember.png</a><br />
<a href="https://www.facebook.com/photo/?fbid=10162651724952579&amp;set=g.137856289571386" target="_blank" class="externalLink" rel="nofollow">https://www.facebook.com/photo/?fbid=10162651724952579&amp;set=g.137856289571386</a><br />
<br />
ΔABC ikizkenar olduğundan ∡ACB = ∡ABC = (180° - 40°) / 2 = 70°<br />
D Noktasından [BC]&#039;ye çizilen paralelin [AB]&#039;yi kestiği nokta G ise;<br />
∡ADG = ∡AGD = 70° = ∡CED ve |DG| = |AF| = |BF|, |AG| = |BG| = |AD| = |CD|<br />
∡ABD = ∡BCE = θ<br />
∡CBE = ∡FBE = ∡DCE = ∡BDG = 70° - θ<br />
∡BDC = 40° + θ<br />
∡BFE = 110° + θ - [FONT=Times New...<br />
<br />
[url=&#039;https://www.sorumvar.net/frm/konular/cemberde-ve-ucgende-aci.14609/&#039;]Çemberde ve Üçgende Açı[/url]]]></content:encoded>
    </item>
    <item>
      <title>Çemberde Çevre Uzunluğu - Dairede Alan</title>
      <pubDate>Thu, 27 Feb 2025 10:15:30 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/cemberde-cevre-uzunlugu-dairede-alan.14523/</link>
      <guid>https://www.sorumvar.net/frm/konular/cemberde-cevre-uzunlugu-dairede-alan.14523/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<img src="https://i.ibb.co/21dMmbYx/Koni.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /><br />
<a href="https://i.ibb.co/21dMmbYx/Koni.png" target="_blank" class="externalLink" rel="nofollow">https://i.ibb.co/21dMmbYx/Koni.png</a><br />
Yayın Denizi 5 TYT Deneme 3<br />
<a href="https://z-library.sk/book/4974680/a240b4/yay%C4%B1n-denizi-5-tyt-deneme-3.html" target="_blank" class="externalLink" rel="nofollow">https://z-library.sk/book/4974680/a240b4/yayın-denizi-5-tyt-deneme-3.html</a><br />
[Sayfa 31 (pdf dosyada 30), Soru 40, Yanıtlar yok]<br />
<br />
Yanal alanı oluşturan r yarıçaplı dairenin 3 / 4&#039;ünün alanı: (3 / 4)·<span style="font-family: 'Times New Roman'"><span style="font-size: 18px">π</span></span>·r^2 birim^2....(I)<br />
AB &quot;BÜYÜK&quot; yayının uzunluğu: (3 / 4)·2<span style="font-family: 'Times New Roman'"><span style="font-size: 18px">π</span></span>·r = 3[FONT=Times...<br />
<br />
[url=&#039;https://www.sorumvar.net/frm/konular/cemberde-cevre-uzunlugu-dairede-alan.14523/&#039;]Çemberde Çevre Uzunluğu - Dairede Alan[/url]]]></content:encoded>
    </item>
    <item>
      <title>Karede, Dairede ve Daire Parçasında Alan</title>
      <pubDate>Wed, 12 Feb 2025 13:24:34 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/karede-dairede-ve-daire-parcasinda-alan.14488/</link>
      <guid>https://www.sorumvar.net/frm/konular/karede-dairede-ve-daire-parcasinda-alan.14488/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<img src="https://i.ibb.co/DfYWFnT2/alan.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /><br />
<a href="https://i.ibb.co/DfYWFnT2/alan.png" target="_blank" class="externalLink" rel="nofollow">https://i.ibb.co/DfYWFnT2/alan.png</a><br />
Hız ve Renk TYT Deneme 4<br />
<a href="https://z-library.sk/book/4974114/ff7f3b/h%C4%B1z-ve-renk-tyt-deneme-4.html" target="_blank" class="externalLink" rel="nofollow">https://z-library.sk/book/4974114/ff7f3b/hız-ve-renk-tyt-deneme-4.html</a><br />
(Sayfa 34, Soru 40, yanıtlar yok)<br />
<br />
S1 = 10^2 - <span style="font-family: 'Times New Roman'"><span style="font-size: 18px">π</span></span>·10^2 / 4 = 100 - 25<span style="font-family: 'Times New Roman'"><span style="font-size: 18px">π</span></span> birim^2....(I)<br />
|AE| = |AC| = (10^2 + 10^2)^0,5 = 10·√2 birim<br />
S2 = (1 / 2)·{ [ <span style="font-family: 'Times New Roman'"><span style="font-size: 18px">π</span></span>·(10·√2)^2·[...<br />
<br />
<a href="https://www.sorumvar.net/frm/konular/karede-dairede-ve-daire-parcasinda-alan.14488/" class="internalLink">Karede, Dairede ve Daire Parçasında Alan</a>]]></content:encoded>
    </item>
    <item>
      <title>Çemberin ve Doğrunun Analitiği - Mutlak Değer Fonksiyonu - İkinci Derece Eşitsizlik</title>
      <pubDate>Fri, 17 Jan 2025 11:22:17 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/cemberin-ve-dogrunun-analitigi-mutlak-deger-fonksiyonu-ikinci-derece-esitsizlik.14433/</link>
      <guid>https://www.sorumvar.net/frm/konular/cemberin-ve-dogrunun-analitigi-mutlak-deger-fonksiyonu-ikinci-derece-esitsizlik.14433/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<img src="https://i.ibb.co/M2Q2L7X/analitik.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /><br />
<a href="https://i.ibb.co/M2Q2L7X/analitik.png" target="_blank" class="externalLink" rel="nofollow">https://i.ibb.co/M2Q2L7X/analitik.png</a><br />
ACİL Yayınları Analitik Geometri Konu Anlatımlı Soru Fasikülü<br />
<a href="https://z-library.sk/book/26142945/8a21e0/analitik-geometri-konu-anlat%C4%B1ml%C4%B1-soru-fasik%C3%BCl%C3%BC.html" target="_blank" class="externalLink" rel="nofollow">https://z-library.sk/book/26142945/8a21e0/analitik-geometri-konu-anlatımlı-soru-fasikülü.html</a><br />
(Son Soru, Yanıtlar: Sondan önceki sayfanın sağ altında)<br />
<br />
Masanın Alanı: x^2 + y^2 ≤ 4^2 ⇒ <span style="color: #0000b3">x^2 + y^2 ≤ 16</span> ⇒ Bir test sınavında <span style="color: #0000b3">D</span> şıkkı işaretlenip geçilir.<br />
Klasik Sınav...<br />
<br />
<a href="https://www.sorumvar.net/frm/konular/cemberin-ve-dogrunun-analitigi-mutlak-deger-fonksiyonu-ikinci-derece-esitsizlik.14433/" class="internalLink">Çemberin ve Doğrunun Analitiği - Mutlak Değer Fonksiyonu - İkinci Derece Eşitsizlik</a>]]></content:encoded>
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    <item>
      <title>Çemberin Analitiği ve Kuvvet Ekseni-Pisagor Teoremi-Trigonometri-Çarpanlara Ayırma</title>
      <pubDate>Mon, 23 Sep 2024 13:07:01 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/cemberin-analitigi-ve-kuvvet-ekseni-pisagor-teoremi-trigonometri-carpanlara-ayirma.14145/</link>
      <guid>https://www.sorumvar.net/frm/konular/cemberin-analitigi-ve-kuvvet-ekseni-pisagor-teoremi-trigonometri-carpanlara-ayirma.14145/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<img src="https://i.ibb.co/ZTTJbFG/Erdem.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /><br />
<a href="https://i.ibb.co/ZTTJbFG/Erdem.png" target="_blank" class="externalLink" rel="nofollow">https://i.ibb.co/ZTTJbFG/Erdem.png</a><br />
<br />
Erdem fantezi yapıp M merkezli ve 5 cm yarıçaplı çemberi x eksenine orijinde teğet olacak şekilde Kartezyen Düzleme taşıdıktan sonra 8 cm yarıçaplı çemberin merkezini de orijin alırsa denklemleri de sırasıyla (x - 0)^2 + (y - 5)^2 = 5^2 ve x^2 + y^2 = 8^2 olarak yazıp açarak taraf tarafa çıkarttığında çemberlerin A ve B olan kesişme noktalarından geçen doğrunun yani kuvvet ekseninin denklemini y = 6,4...<br />
<br />
<a href="https://www.sorumvar.net/frm/konular/cemberin-analitigi-ve-kuvvet-ekseni-pisagor-teoremi-trigonometri-carpanlara-ayirma.14145/" class="internalLink">Çemberin Analitiği ve Kuvvet Ekseni-Pisagor Teoremi-Trigonometri-Çarpanlara Ayırma</a>]]></content:encoded>
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    <item>
      <title>Çemberde Teğet Kiriş ve Merkez Açılar ile Yay İlişkisi</title>
      <pubDate>Tue, 06 Aug 2024 15:39:14 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/cemberde-teget-kiris-ve-merkez-acilar-ile-yay-iliskisi.14047/</link>
      <guid>https://www.sorumvar.net/frm/konular/cemberde-teget-kiris-ve-merkez-acilar-ile-yay-iliskisi.14047/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[University of Calgary - CA, &quot;Junior Math Contest&quot; 2024 çözümlü sorularından birinin TYT uyarlaması:<br />
<br />
<img src="https://i.ibb.co/YdD2XkV/Calgary.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /><br />
<a href="https://i.ibb.co/YdD2XkV/Calgary.png" target="_blank" class="externalLink" rel="nofollow">https://i.ibb.co/YdD2XkV/Calgary.png</a><br />
<br />
<i><span style="font-size: 18px"><span style="color: #660000">Şekildeki çember [AB] kirişiyle 5 / 7 oranında iki daire parçası alanına bölündüğüne göre teğet kiriş açı kaç derecedir?<br />
<br />
A) 15<br />
B) 30<br />
C) 45<br />
D) 60<br />
E) 75</span></span></i><br />
<br />
Teğet-Kiriş Açı: θ<br />
Merkez Açı: 2θ<br />
Çemberin Yarıçapı: r<br />
Daire parçalarının alanlarının oranı, karşılıklı...<br />
<br />
<a href="https://www.sorumvar.net/frm/konular/cemberde-teget-kiris-ve-merkez-acilar-ile-yay-iliskisi.14047/" class="internalLink">Çemberde Teğet Kiriş ve Merkez Açılar ile Yay İlişkisi</a>]]></content:encoded>
    </item>
    <item>
      <title>Altın Oran - Pisagor Teoremi - Çemberde ve Üçgende Uzunluk - Trigonometri</title>
      <pubDate>Thu, 13 Jun 2024 10:41:23 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/altin-oran-pisagor-teoremi-cemberde-ve-ucgende-uzunluk-trigonometri.13917/</link>
      <guid>https://www.sorumvar.net/frm/konular/altin-oran-pisagor-teoremi-cemberde-ve-ucgende-uzunluk-trigonometri.13917/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<a href="https://servimg.com/view/19971039/4217" target="_blank" class="externalLink" rel="nofollow"><img src="https://i72.servimg.com/u/f72/19/97/10/39/altnor10.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /></a><br />
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Endemik Yayınları, 12 TYT Matematik Denemesi<br />
<a href="https://singlelogin.re/book/3641088/73e6c0/endemik-12-tyt-matematik-deneme.html" target="_blank" class="externalLink" rel="nofollow">https://singlelogin.re/book/3641088/73e6c0/endemik-12-tyt-matematik-deneme.html</a><br />
(Son Soru, Yanıtlar: Son Sayfa)<br />
<br />
Pisagor Teoremi nedeniyle |BC| = [ (1 / 2)^2 + 1^2 ]^0,5 = √5 / 2<br />
|AB| + |BD| = 1 / 2 + √5 / 2 = (√5 + 1) / 2 = <span style="color: #0000b3">|AD|</span>....<br />
<br />
<a href="https://www.sorumvar.net/frm/konular/altin-oran-pisagor-teoremi-cemberde-ve-ucgende-uzunluk-trigonometri.13917/" class="internalLink">Altın Oran - Pisagor Teoremi - Çemberde ve Üçgende Uzunluk - Trigonometri</a>]]></content:encoded>
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    <item>
      <title>Çemberde ve Üçgende Açı - Trigonometri</title>
      <pubDate>Sat, 01 Jun 2024 09:43:00 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/cemberde-ve-ucgende-aci-trigonometri.13887/</link>
      <guid>https://www.sorumvar.net/frm/konular/cemberde-ve-ucgende-aci-trigonometri.13887/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<a href="https://servimg.com/view/19971039/4197" target="_blank" class="externalLink" rel="nofollow"><img src="https://i72.servimg.com/u/f72/19/97/10/39/zember95.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /></a><br />
<a href="https://i72.servimg.com/u/f72/19/97/10/39/zember95.png" target="_blank" class="externalLink" rel="nofollow">https://i72.servimg.com/u/f72/19/97/10/39/zember95.png</a><br />
<a href="https://www.facebook.com/photo/?fbid=10232986708359016&amp;set=gm.7443266172432482&amp;idorvanity=703383433087490" target="_blank" class="externalLink" rel="nofollow">https://www.facebook.com/photo/?fbi...m.7443266172432482&amp;idorvanity=703383433087490</a><br />
<br />
Çemberin Yarıçapı: r birim<br />
ΔDEO İkizkenar dik üçgen<br />
∡AOD = ∡COE = θ<br />
∡DOC = 90° - θ<br />
∡OCE = ∡OEC = 90° - θ / 2<br />
∡DEC = (1 / 2)·∡DOC = (1 / 2)·(90° - θ) = 45° - θ / 2 = ∡AEC<br />
ΔCEO İkizkenar üçgeninde...<br />
<br />
<a href="https://www.sorumvar.net/frm/konular/cemberde-ve-ucgende-aci-trigonometri.13887/" class="internalLink">Çemberde ve Üçgende Açı - Trigonometri</a>]]></content:encoded>
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