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  <channel>
    <title>Ivır Zıvır Sorular - Sohbet (Trivial Questions - Chat)</title>
    <description>Ivır Zıvır Sorular - Sohbet (Trivial Questions - Chat)</description>
    <pubDate>Mon, 07 Sep 2026 17:29:19 +0000</pubDate>
    <lastBuildDate>Mon, 07 Sep 2026 17:29:19 +0000</lastBuildDate>
    <generator>SorumVar.Net</generator>
    <link>https://www.sorumvar.net/frm/konu/ivir-zivir-sorular-sohbet-trivial-questions-chat.53/</link>
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    <item>
      <title>Kinematics and Free Fall Problem (7th Grade)</title>
      <pubDate>Mon, 07 Sep 2026 13:00:18 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/kinematics-and-free-fall-problem-7th-grade.15762/</link>
      <guid>https://www.sorumvar.net/frm/konular/kinematics-and-free-fall-problem-7th-grade.15762/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[From Santa Rosa Junior (Two-Year Community) College: (<i>I have added an extra question between the parentheses.</i>)<br />
<br />
<i><span style="font-size: 18px"><span style="color: #660000">The distance, s, in feet, traveled by a body falling freely from rest in t seconds is approximated by the function s(t) = 16t^2. An experimenter on a ladder releases a marble from rest. The marble takes 3 seconds to fall to the ground. How high was the marble when it was released (and what is the gravitational acceleration)?</span></span></i><br />
<br />
S =...<br />
<br />
<a href="https://www.sorumvar.net/frm/konular/kinematics-and-free-fall-problem-7th-grade.15762/" class="internalLink">Kinematics and Free Fall Problem (7th Grade)</a>]]></content:encoded>
    </item>
    <item>
      <title>Dört Bilinmeyenli Lineer Denklem Çözümü (Hamallığı)</title>
      <pubDate>Mon, 07 Sep 2026 11:35:38 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/dort-bilinmeyenli-lineer-denklem-cozumu-hamalligi.15761/</link>
      <guid>https://www.sorumvar.net/frm/konular/dort-bilinmeyenli-lineer-denklem-cozumu-hamalligi.15761/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<i><span style="font-size: 18px"><span style="color: #660000">3. dereceden bir P(x) polinomu için P(2) = P(3) = P(4) = 0 ve P(1) = −12 ise polinomu bulunuz.</span></span></i><br />
<a href="https://0dandereceye.com.tr/wp-content/uploads/2026/08/0dan-Dereceye-Sinava-Hazirlanma-El-Kitabi-II.-Genisleme-Paketi-1.-Gun.pdf" target="_blank" class="externalLink" rel="nofollow">https://0dandereceye.com.tr/wp-cont...nma-El-Kitabi-II.-Genisleme-Paketi-1.-Gun.pdf</a><br />
(Son soru, yanıtlar sayfanın altında)<br />
<br />
a, b, c, d ∈ R, P(x) = a·x^3 + b·x^2 + c·x + d<br />
8a + 4b + 2c + d = 0....(I)<br />
27a + 9b + 3c + d = 0....(II)<br />
64a + 16b + 4c + d = 0....(III)<br />
a + b + c + d = -12....(IV)<br />
Bu problem için...<br />
<br />
<a href="https://www.sorumvar.net/frm/konular/dort-bilinmeyenli-lineer-denklem-cozumu-hamalligi.15761/" class="internalLink">Dört Bilinmeyenli Lineer Denklem Çözümü (Hamallığı)</a>]]></content:encoded>
    </item>
    <item>
      <title>Paraboller Arası Alan - İntegral</title>
      <pubDate>Sun, 06 Sep 2026 10:57:36 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/paraboller-arasi-alan-integral.15758/</link>
      <guid>https://www.sorumvar.net/frm/konular/paraboller-arasi-alan-integral.15758/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<a href="https://servimg.com/view/19971039/5524" target="_blank" class="externalLink" rel="nofollow"><img src="https://i72.servimg.com/u/f72/19/97/10/39/integr55.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /></a><br />
<a href="https://i72.servimg.com/u/f72/19/97/10/39/integr55.png" target="_blank" class="externalLink" rel="nofollow">https://i72.servimg.com/u/f72/19/97/10/39/integr55.png</a><br />
<a href="https://0dandereceye.com.tr/wp-content/uploads/2026/08/0dan-Dereceye-Sinava-Hazirlanma-El-Kitabi-II.-Genisleme-Paketi-3.-Gun.pdf" target="_blank" class="externalLink" rel="nofollow">https://0dandereceye.com.tr/wp-cont...nma-El-Kitabi-II.-Genisleme-Paketi-3.-Gun.pdf</a><br />
(Son soru, yanıtlar o sayfanın sol alt tarafında)<br />
<br />
<a href="https://servimg.com/view/19971039/5525" target="_blank" class="externalLink" rel="nofollow"><img src="https://i72.servimg.com/u/f72/19/97/10/39/integr56.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /></a>...<br />
<br />
<a href="https://www.sorumvar.net/frm/konular/paraboller-arasi-alan-integral.15758/" class="internalLink">Paraboller Arası Alan - İntegral</a>]]></content:encoded>
    </item>
    <item>
      <title>Fonksiyonlar</title>
      <pubDate>Sat, 05 Sep 2026 18:04:07 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/fonksiyonlar.15757/</link>
      <guid>https://www.sorumvar.net/frm/konular/fonksiyonlar.15757/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<i><span style="font-size: 18px"><span style="color: #660000">f(4x + 3) = 3x + 4 ⇒ f(0) = ?</span></span></i><br />
<br />
<span style="text-decoration: underline"><i>Çözüm - 1:</i></span> f[ 4·(-3 / 4) + 3 ] = 3·(-3 / 4) + 4 = -9 / 4 + 4 = (-9 + 16) / 4 = <span style="color: #0000b3">7 / 4</span>.<br />
<br />
<i><span style="text-decoration: underline">Çözüm - 2:</span></i> 4x + 3 = y ⇒ x = (y - 3) / 4 ⇒ f(y) = 3·[ (y - 3) / 4 ] + 4 ⇒ f(0) = 3·[ (0 - 3) / 4 ] + 4 = -9 / 4 + 4 = <span style="color: #0000b3">7 / 4</span>.<br />
<br />
<a href="https://matematiknotu.com/wp-content/uploads/2020/02/Fonksiyonlar-Baslangic-Testi-4.pdf" target="_blank" class="externalLink" rel="nofollow">https://matematiknotu.com/wp-content/uploads/2020/02/Fonksiyonlar-Baslangic-Testi-4.pdf</a><br />
(Soru 1, yanıtlar son sayfanın sağ alt...<br />
<br />
<a href="https://www.sorumvar.net/frm/konular/fonksiyonlar.15757/" class="internalLink">Fonksiyonlar</a>]]></content:encoded>
    </item>
    <item>
      <title>Orantı - Doğrunun Analitiği - İki Bilinmeyenli Denklem (8. Sınıf)</title>
      <pubDate>Thu, 03 Sep 2026 12:12:31 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/oranti-dogrunun-analitigi-iki-bilinmeyenli-denklem-8-sinif.15754/</link>
      <guid>https://www.sorumvar.net/frm/konular/oranti-dogrunun-analitigi-iki-bilinmeyenli-denklem-8-sinif.15754/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<span style="color: #660000"><span style="font-size: 15px"><a href="https://servimg.com/view/19971039/5523" target="_blank" class="externalLink" rel="nofollow"><img src="https://i72.servimg.com/u/f72/19/97/10/39/af10.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /></a><br />
<a href="https://i72.servimg.com/u/f72/19/97/10/39/af10.png" target="_blank" class="externalLink" rel="nofollow">https://i72.servimg.com/u/f72/19/97/10/39/af10.png</a></span></span><br />
<i><span style="font-size: 18px"><span style="color: #660000">Yusuf Bey, 3600₺ parayı yaşları sırasıyla 8 ve 10 olan Ahmet ve Furkan isimli iki oğluna yaşlarıyla orantılı şekilde paylaştırıyor ve çocuklar her gün düzenli olarak harcamaya başlıyorlar. Yukarıdaki grafikte Ahmet ve Furkan&#039;ın paylarına düşen paraların...</span></span></i><br />
<br />
<a href="https://www.sorumvar.net/frm/konular/oranti-dogrunun-analitigi-iki-bilinmeyenli-denklem-8-sinif.15754/" class="internalLink">Orantı - Doğrunun Analitiği - İki Bilinmeyenli Denklem (8. Sınıf)</a>]]></content:encoded>
    </item>
    <item>
      <title>Bağımsız Olayların Olasılığı - Rasyonel Sayılarla Toplama</title>
      <pubDate>Wed, 02 Sep 2026 12:11:22 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/bagimsiz-olaylarin-olasiligi-rasyonel-sayilarla-toplama.15749/</link>
      <guid>https://www.sorumvar.net/frm/konular/bagimsiz-olaylarin-olasiligi-rasyonel-sayilarla-toplama.15749/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<img src="https://i.ibb.co/s91m3CqZ/dart.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /><br />
<a href="https://i.ibb.co/s91m3CqZ/dart.png" target="_blank" class="externalLink" rel="nofollow">https://i.ibb.co/s91m3CqZ/dart.png</a><br />
<a href="https://drive.google.com/drive/folders/14ye9s-cACH9_tvLNYDjud7d3B47Vs1Wk" target="_blank" class="externalLink" rel="nofollow">https://drive.google.com/drive/folders/14ye9s-cACH9_tvLNYDjud7d3B47Vs1Wk</a><br />
(1,2 GigaByte&#039;lık sıkıştırılmış dosyadan çıkanlar arasındaki 9. Sınıf Matematik Soru Bankası, Sayfa 349, Soru 8, Yanıtlar: Sayfa 367, Test - 4 / Sarmal Test - 11)<br />
<br />
a = P(Mavi Ok) = 1 / 3<br />
b = P(Herhangi Bir Ok Seçimi ∩ Sarı Bölgeye Vuruş) = 1·(4 / 8) = 1 / 2<br />
a + b = 1 / 3 + 1 / 2 = (2 + 3) / (3·2) = <span style="color: #0000b3">5 /...</span><br />
<br />
<a href="https://www.sorumvar.net/frm/konular/bagimsiz-olaylarin-olasiligi-rasyonel-sayilarla-toplama.15749/" class="internalLink">Bağımsız Olayların Olasılığı - Rasyonel Sayılarla Toplama</a>]]></content:encoded>
    </item>
    <item>
      <title>İkinci Derece İki Bilinmeyenli Denklemler (7. Sınıf)</title>
      <pubDate>Tue, 01 Sep 2026 12:46:54 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/ikinci-derece-iki-bilinmeyenli-denklemler-7-sinif.15747/</link>
      <guid>https://www.sorumvar.net/frm/konular/ikinci-derece-iki-bilinmeyenli-denklemler-7-sinif.15747/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<i><span style="font-size: 18px"><span style="color: #660000">x^2 - y = -2, 2x - y = -1, x - y = ?</span></span></i><br />
<a href="https://matematiknotu.com/wp-content/uploads/2021/02/Denklen-Sistemleri-Test-3.pdf" target="_blank" class="externalLink" rel="nofollow">https://matematiknotu.com/wp-content/uploads/2021/02/Denklen-Sistemleri-Test-3.pdf</a><br />
(Son soru, yanıtlar sorunun altında)<br />
<br />
Denklemler taraf tarafa çıkarılınca x^2 - 2x + 1 = 0 ⇒ (x - 1)^2 = 0 ⇒ x = 1 değeri denklemlerden birinde, örneğin ikincisinde kullanılıp<br />
2 + 1 = y = 3 ⇒ x - y = 1 - 3 = <span style="color: #0000b3">-2</span>.]]></content:encoded>
    </item>
    <item>
      <title>Modüler Aritmetik - İki Bilinmeyenli Denklem (8. Sınıf)</title>
      <pubDate>Mon, 31 Aug 2026 09:59:51 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/moduler-aritmetik-iki-bilinmeyenli-denklem-8-sinif.15744/</link>
      <guid>https://www.sorumvar.net/frm/konular/moduler-aritmetik-iki-bilinmeyenli-denklem-8-sinif.15744/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<i><span style="font-size: 18px"><span style="color: #660000">Bir öğretmen öğrencilerinin her birine 4 çikolata verirse 3 tane arttığını görüp öğrenci başına bir fazla olması durumunda 17 çikolataya daha ihtiyacı olduğunu anlıyorsa kaç çikolatası vardır?<br />
<br />
A) 55<br />
B) 68<br />
C) 83<br />
D) 101<br />
E) 107</span></span></i><br />
<br />
<span style="text-decoration: underline"><i>Çözüm - 1 (Test Sınavında):</i></span><br />
Ç ≡ 3(Mod 4) ⇒ Ç - 3 ≡ 0(Mod 4) ===&gt; Ç1 = 55 V Ç2 = 83<br />
Ç + 17 ≡ 0(Mod 5) ===&gt; <span style="color: #0000b3">83</span> + 17 ≡ 0(Mod 5)<br />
<br />
<span style="text-decoration: underline"><i>Çözüm - 2 (Seçeneksiz açık uçlu veya klasik...</i></span><br />
<br />
<a href="https://www.sorumvar.net/frm/konular/moduler-aritmetik-iki-bilinmeyenli-denklem-8-sinif.15744/" class="internalLink">Modüler Aritmetik - İki Bilinmeyenli Denklem (8. Sınıf)</a>]]></content:encoded>
    </item>
    <item>
      <title>Natural, Exponential and Radical Numbers - Probability (8th Grade)</title>
      <pubDate>Sun, 30 Aug 2026 11:21:02 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/natural-exponential-and-radical-numbers-probability-8th-grade.15742/</link>
      <guid>https://www.sorumvar.net/frm/konular/natural-exponential-and-radical-numbers-probability-8th-grade.15742/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<i><span style="font-size: 18px"><span style="color: #660000">What is the probability that the product of the square root of a natural number between 1 and 100 (inclusive) and the number 3^0.5 is also a natural number?</span></span></i><br />
<br />
x: Perfect Square<br />
3x ≤ 100 ⇒ x ≤ 100 / 3 ⇒ x = {1^2, 2^2, 3^2, 4^2, 5^2} ⇒ s(x) = 5<br />
Probability = 5 / 100 = <span style="color: #0000b3">1 / 20</span>.<br />
<br />
<span style="text-decoration: underline"><i>Original Question (Turkish):</i></span> &quot;Son Kontrol, Matematik&quot;, Bilfen Yayınları, Temmuz 2025, Sayfa 79, Soru 3]]></content:encoded>
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    <item>
      <title>Tam Kare Yapılar - Çemberin Analitiği - Eşitsizlik</title>
      <pubDate>Sat, 29 Aug 2026 11:04:06 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/tam-kare-yapilar-cemberin-analitigi-esitsizlik.15740/</link>
      <guid>https://www.sorumvar.net/frm/konular/tam-kare-yapilar-cemberin-analitigi-esitsizlik.15740/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<i><span style="font-size: 18px"><span style="color: #660000">k ∈ R ve analitik düzlemde x^2 + k·y^2 + (k + 3)x – (k + 5)y + m + 1 = 0 denklemi bir çember belirttiğine göre k + m’nin alabileceği en büyük tam sayı değeri kaçtır?<br />
<br />
A) 14<br />
B) 13<br />
C) 12<br />
D) 11<br />
E) 10</span></span></i><br />
<br />
x^2 teriminin katsayısı 1 olduğundan denklemin çember olabilmesi için k = 1 nedeniyle x^2 + y^2 + 4x - 6y + m + 1 = 0 çemberine göre;<br />
x^2 + 4x + 4 - 4 + y^2 - 6y + 9 - 9 + m + 1 = 0<br />
(x + 2)^2 - 4 + (y - 3)^2 - 9 + m + 1 = 0<br />
(x + 2)^2 + (y - 3)^2 = 12 - m &gt;...<br />
<br />
<a href="https://www.sorumvar.net/frm/konular/tam-kare-yapilar-cemberin-analitigi-esitsizlik.15740/" class="internalLink">Tam Kare Yapılar - Çemberin Analitiği - Eşitsizlik</a>]]></content:encoded>
    </item>
    <item>
      <title>Tam Kare Yapılar - Çemberin, Noktanın ve Doğrunun Analitiği</title>
      <pubDate>Fri, 28 Aug 2026 11:54:47 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/tam-kare-yapilar-cemberin-noktanin-ve-dogrunun-analitigi.15738/</link>
      <guid>https://www.sorumvar.net/frm/konular/tam-kare-yapilar-cemberin-noktanin-ve-dogrunun-analitigi.15738/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<i><span style="font-size: 18px"><span style="color: #660000">Denklemi x^2 + y^2 – 6x + 4y + 9 = 0 olan çemberin merkezinin 4x + 3y + n = 0 doğrusuna uzaklığı 3 birimse n = ? <br />
<br />
A) –15<br />
B) –8<br />
C) 9<br />
D) 16<br />
E) 21</span></span></i><br />
<br />
<a href="https://cdn.eba.gov.tr/yardimcikaynaklar/2022/01/odsgm/calisma/2122/Lise/AYT/AYT_Gumushane.pdf" target="_blank" class="externalLink" rel="nofollow">https://cdn.eba.gov.tr/yardimcikaynaklar/2022/01/odsgm/calisma/2122/Lise/AYT/AYT_Gumushane.pdf</a><br />
(Sayfa 33, Soru 44, Yanıtlar son sayfada)<br />
<br />
x^2 - 6x + 9 - 9 + y^2 + 4y + 4 - 4 + 9 = 0<br />
(x - 3)^2 - 9 + (y + 2)^2 - 4 + 9 = 0<br />
(x - 3)^2 + (y + 2)^2 = 4<br />
Çemberin Merkezi: M(3, -2)<br />
Merkezin 4x + 3y + n = 0...<br />
<br />
<a href="https://www.sorumvar.net/frm/konular/tam-kare-yapilar-cemberin-noktanin-ve-dogrunun-analitigi.15738/" class="internalLink">Tam Kare Yapılar - Çemberin, Noktanın ve Doğrunun Analitiği</a>]]></content:encoded>
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    <item>
      <title>Equation (6th Grade)</title>
      <pubDate>Thu, 27 Aug 2026 18:00:52 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/equation-6th-grade.15737/</link>
      <guid>https://www.sorumvar.net/frm/konular/equation-6th-grade.15737/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<img src="https://i.ibb.co/ns4vhvDF/xyz.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /><br />
<a href="https://i.ibb.co/ns4vhvDF/xyz.png" target="_blank" class="externalLink" rel="nofollow">https://i.ibb.co/ns4vhvDF/xyz.png</a><br />
<a href="https://test-ninjas.com/sat-math-practice" target="_blank" class="externalLink" rel="nofollow">https://test-ninjas.com/sat-math-practice</a><br />
(2nd Question)<br />
<br />
x·1 + 6·3 + 15·20 = 360 ⇒ x = 360 - 300 - 18 = <span style="color: #0000b3">42 sandwiches</span>.]]></content:encoded>
    </item>
    <item>
      <title>Two-Variable Linear Equations (8th Grade)</title>
      <pubDate>Thu, 27 Aug 2026 09:46:09 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/two-variable-linear-equations-8th-grade.15735/</link>
      <guid>https://www.sorumvar.net/frm/konular/two-variable-linear-equations-8th-grade.15735/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<span style="font-size: 18px"><span style="color: #660000"><i>In a classroom, if students sit two to a desk and nine remain standing, but if they sit three to a desk and two desks remain empty, how many students are there?</i></span></span><br />
<br />
Students = 2·Desk + 9<br />
Students = 3·(Desk - 2) + 0<br />
Multiplying the first equation by 3, and the second equation by -2,<br />
3·Students = 6·Desk + 27<br />
-2·Students = -6·(Desk - 2)<br />
Summing both equations side by side,<br />
Students = 27 + 12 = <span style="color: #0000b3">39</span>.<br />
<br />
<span style="text-decoration: underline"><i>Original Question...</i></span><br />
<br />
<a href="https://www.sorumvar.net/frm/konular/two-variable-linear-equations-8th-grade.15735/" class="internalLink">Two-Variable Linear Equations (8th Grade)</a>]]></content:encoded>
    </item>
    <item>
      <title>Line Equation (8th Grade)</title>
      <pubDate>Wed, 26 Aug 2026 14:22:08 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/line-equation-8th-grade.15733/</link>
      <guid>https://www.sorumvar.net/frm/konular/line-equation-8th-grade.15733/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<i><span style="font-size: 18px"><span style="color: #660000">The data showing the revenue based on the number of T-shirts sold at a store is provided below:<br />
The Number of Sales: x = {1, 2, 3, ...}<br />
Revenue (TL): y = {350, 700, 1050, ...}<br />
What is the equation showing the linear relationship between the number of T-shirts sold and the revenue generated?</span></span></i><br />
<br />
(y - 350) / (350 - 700) = (x - 1) / (1 - 2) ⇒ <span style="color: #0000b3">y = 350·x</span>.<br />
<br />
<span style="text-decoration: underline"><i>Note:</i></span> <br />
350 = 1·350<br />
700 = 2·350<br />
1050 = 3·350<br />
...<br />
<br />
<span style="text-decoration: underline"><i>Source...</i></span><br />
<br />
<a href="https://www.sorumvar.net/frm/konular/line-equation-8th-grade.15733/" class="internalLink">Line Equation (8th Grade)</a>]]></content:encoded>
    </item>
    <item>
      <title>Sabit Fonksiyon - Belirsiz Katsayılar Kuralı</title>
      <pubDate>Wed, 26 Aug 2026 12:00:14 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/sabit-fonksiyon-belirsiz-katsayilar-kurali.15732/</link>
      <guid>https://www.sorumvar.net/frm/konular/sabit-fonksiyon-belirsiz-katsayilar-kurali.15732/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<i><span style="font-size: 18px"><span style="color: #660000">m ∈ R ve f(x) = (m·x + 3) / (3x - 1) sabit fonksiyon ise f(m) = ?</span></span></i><br />
<br />
<a href="https://matematiknotu.com/wp-content/uploads/2020/02/Fonksiyonlar%C4%B1n-Sabit-ve-Do%C4%9Frusall%C4%B1%C4%9F%C4%B1-Temel-Testi-1.pdf" target="_blank" class="externalLink" rel="nofollow">https://matematiknotu.com/wp-conten...ların-Sabit-ve-Doğrusallığı-Temel-Testi-1.pdf</a><br />
(Son soru, Yanıtlar o sayfanın sol alt tarafında)<br />
<br />
k ∈ R ⇒ f(x) = (m·x + 3) / (3x - 1) = k ⇒ m·x + 3 = 3k·x - k ⇒ m = 3k, k = -3 [ ⇒ m = 3(-3) = -9 ===&gt; Bu işlem gereksiz. ]<br />
f(m) = k = <span style="color: #0000b3">-3</span>.<br />
<br />
<span style="text-decoration: underline"><i>Not:</i></span> Soruyu ben...<br />
<br />
<a href="https://www.sorumvar.net/frm/konular/sabit-fonksiyon-belirsiz-katsayilar-kurali.15732/" class="internalLink">Sabit Fonksiyon - Belirsiz Katsayılar Kuralı</a>]]></content:encoded>
    </item>
    <item>
      <title>Üstel Sayılar -  Ardışık Doğal Sayıların Toplamı - İkinci Derece Denklemde Çarpanlara Ayırma</title>
      <pubDate>Tue, 25 Aug 2026 17:46:06 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/ustel-sayilar-ardisik-dogal-sayilarin-toplami-ikinci-derece-denklemde-carpanlara-ayirma.15731/</link>
      <guid>https://www.sorumvar.net/frm/konular/ustel-sayilar-ardisik-dogal-sayilarin-toplami-ikinci-derece-denklemde-carpanlara-ayirma.15731/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<img src="https://i.ibb.co/Kjv0Tkmy/ustel.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /><br />
<a href="https://i.ibb.co/Kjv0Tkmy/ustel.png" target="_blank" class="externalLink" rel="nofollow">https://i.ibb.co/Kjv0Tkmy/ustel.png</a><br />
<a href="https://www.scribd.com/document/871375615/345-AYT-Matematik-Brans-Denemesi-2025-yks-arsiv" target="_blank" class="externalLink" rel="nofollow">https://www.scribd.com/document/871375615/345-AYT-Matematik-Brans-Denemesi-2025-yks-arsiv</a><br />
(Sayfa 4, Soru 1, Yanıtlar: Sayfa 116, Test 1)<br />
<br />
[ 4^(1 + 2 + 3) ]·[ 8^(1 + 2 + 3 + 4) ] = 4^[ n(n + 1) / 2 ]<br />
{ 2^[ 2·(3·4) / 2 ] }·{ 2^[ 3·(4·5) / 2 ] } = 2^{ 2·[ n·(n + 1) / 2 ] }<br />
[ 2·(3·4) / 2 ] + [ 3·(4·5) / 2 =  2·[ n·(n + 1) / 2<br />
12 + 30 = n^2 + n<br />
(n + 7)(n - 6) = 0<br />
n = <span style="color: #0000b3">6</span> &gt; 0.]]></content:encoded>
    </item>
    <item>
      <title>Trigonometrik Limit</title>
      <pubDate>Tue, 25 Aug 2026 13:20:37 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/trigonometrik-limit.15730/</link>
      <guid>https://www.sorumvar.net/frm/konular/trigonometrik-limit.15730/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<a href="https://servimg.com/view/19971039/5514" target="_blank" class="externalLink" rel="nofollow"><img src="https://i72.servimg.com/u/f72/19/97/10/39/limit50.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /></a><br />
<a href="https://i72.servimg.com/u/f72/19/97/10/39/limit50.png" target="_blank" class="externalLink" rel="nofollow">https://i72.servimg.com/u/f72/19/97/10/39/limit50.png</a><br />
<a href="https://matematiknotu.com/wp-content/uploads/2021/03/Limit-Kavrama-Testi-6.pdf" target="_blank" class="externalLink" rel="nofollow">https://matematiknotu.com/wp-content/uploads/2021/03/Limit-Kavrama-Testi-6.pdf</a><br />
(Son soru, Yanıtlar sayfanın sağ üst tarafında)<br />
<br />
| sin(6<span style="font-family: 'Times New Roman'"><span style="font-size: 18px">π</span></span>) + cos(10<span style="font-family: 'Times New Roman'"><span style="font-size: 18px">π</span></span>) | / cos(3<span style="font-family: 'Times New Roman'"><span style="font-size: 18px">π</span></span>) = | 0 + 1 | /...<br />
<br />
<a href="https://www.sorumvar.net/frm/konular/trigonometrik-limit.15730/" class="internalLink">Trigonometrik Limit</a>]]></content:encoded>
    </item>
    <item>
      <title>Slope and Equation of Lines - One Variable Linear Equation</title>
      <pubDate>Mon, 24 Aug 2026 18:48:48 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/slope-and-equation-of-lines-one-variable-linear-equation.15729/</link>
      <guid>https://www.sorumvar.net/frm/konular/slope-and-equation-of-lines-one-variable-linear-equation.15729/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<a href="https://servimg.com/view/19971039/5513" target="_blank" class="externalLink" rel="nofollow"><img src="https://i72.servimg.com/u/f72/19/97/10/39/lines12.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /></a><br />
<a href="https://i72.servimg.com/u/f72/19/97/10/39/lines12.png" target="_blank" class="externalLink" rel="nofollow">https://i72.servimg.com/u/f72/19/97/10/39/lines12.png</a><br />
<a href="https://www.scribd.com/document/112554239/SAT-math" target="_blank" class="externalLink" rel="nofollow">https://www.scribd.com/document/112554239/SAT-math</a><br />
(The last question, Answers: Next page)<br />
<br />
Equation of the line [YZ]: y - 5 = (-4 / 5)(x - 4)<br />
x-Intercept of the line [YZ]: 0 - 5 = (-4 / 5)(x - 4) ⇒ x = 25 / 4 + 4 = (25 + 16) / 4 = 41 / 4 = <span style="color: #0000b3">10 + 1 / 4</span>.]]></content:encoded>
    </item>
    <item>
      <title>Speed, Time, and Distance (8th Grade)</title>
      <pubDate>Mon, 24 Aug 2026 14:56:27 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/speed-time-and-distance-8th-grade.15728/</link>
      <guid>https://www.sorumvar.net/frm/konular/speed-time-and-distance-8th-grade.15728/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[From the University of Colorado - Boulder (I have changed the tenses to have better time consistency):<br />
<br />
<i><span style="font-size: 18px"><span style="color: #660000">The Walker family decided to attend a wedding out of town. Betty and Harold Walker left a day early and arrived in 3.5 hours at the town where the wedding was going to take place. If Mary and Jane Walker left the morning of the wedding, drove an average of 10 miles per hour faster than their siblings had done the day before, and arrived in 3 hours, how far away was...</span></span></i><br />
<br />
<a href="https://www.sorumvar.net/frm/konular/speed-time-and-distance-8th-grade.15728/" class="internalLink">Speed, Time, and Distance (8th Grade)</a>]]></content:encoded>
    </item>
    <item>
      <title>Parabol - Türev - İki Bilinmeyenli Denklem</title>
      <pubDate>Mon, 24 Aug 2026 13:04:50 +0000</pubDate>
      <link>https://www.sorumvar.net/frm/konular/parabol-turev-iki-bilinmeyenli-denklem.15727/</link>
      <guid>https://www.sorumvar.net/frm/konular/parabol-turev-iki-bilinmeyenli-denklem.15727/</guid>
      <author>Honore</author>
      <dc:creator>Honore</dc:creator>
      <content:encoded><![CDATA[<img src="https://i.ibb.co/p6p7fqy0/parabol.png" class="bbCodeImage LbImage" alt="[&#x200B;IMG]" /><br />
<a href="https://i.ibb.co/p6p7fqy0/parabol.png" target="_blank" class="externalLink" rel="nofollow">https://i.ibb.co/p6p7fqy0/parabol.png</a><br />
<a href="https://matematiknotu.com/wp-content/uploads/2020/02/Grafi%C4%9Fi-Verilen-Parabol%C3%BCn-Denklemi-Testi-1.pdf" target="_blank" class="externalLink" rel="nofollow">https://matematiknotu.com/wp-content/uploads/2020/02/Grafiği-Verilen-Parabolün-Denklemi-Testi-1.pdf</a><br />
(Son soru, Yanıtlar o sayfanın sol alt tarafında)<br />
<br />
a, b ∈ R<br />
y = f(x) = a·x^2 + b·x<br />
f(1) = 3 ⇒ a + b = -3....(I)<br />
f &#039;(x) = 2a·x + b = 0 ⇒ x = -b / (2a) = -2 ⇒ b = 4a....(II)<br />
(II) eşitliği (I) denklemindeki yerine yazılınca a + 4a = -3 ⇒ a = -3 / 5....(III)<br />
(III) değerine göre (II)...<br />
<br />
<a href="https://www.sorumvar.net/frm/konular/parabol-turev-iki-bilinmeyenli-denklem.15727/" class="internalLink">Parabol - Türev - İki Bilinmeyenli Denklem</a>]]></content:encoded>
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