Çözüldü Probability - Combination

Of the properties in a real estate agent's advertisement listing; two 1+1 (one bed room + one living room) houses, and one 2+1 house all of which are for rental; two 2+1 houses, and one 1+1 house all of which are for sale. What is the probability that the number of 2+1 houses for sale becomes equal to the number of 2+1 houses for rent when any two of these ads are removed?

Total number of cases: C(6, 2) = 15
Considering the picture in the original question;
Rent (1 + 1): A
Sale (2 + 1): B
Rent (2 + 1): C
Rent (1 + 1): D
Sale (2 + 1): E
Sale (1 + 1): F
Suitable cases: 6 (A-B, A-E, D-B, D-E, F-B, F-E)
Probability: 6 / 15 = 2 / 5.

Solution by the AI at www.mathful.com is attached.

Original Question (Turkish):

https://i72.servimg.com/u/f72/19/97/10/39/emlak10.png
https://drive.google.com/uc?export=download&id=1_f-eY_uhvSMzVPG1m5ho1MSaa5sqFS4N
(Son soru, yanıtlar yok.)