Çözüldü Karmaşık Sayılarda Kökler

z^3 = -8i = 8e^[ i·(3π / 2) ]
z(k) = [ (2^3)^(1 / 3) ] · { cos[ (3π / 2 + k·2π) / 3 ] + i·sin[ (3π / 2 + k·2π) / 3 ] }, k = 0, 1, 2
z(0) = 2e^[ i·(π / 2) ] = 2[cos(π / 2) + i·sin(π / 2) ] = 2i
z(1) = 2e^[ i·(7π / 6) ] = 2[cos(7π / 6) + i·sin(7π / 6) ] = 2[-cos(π / 6) - i·sin(π / 6) ] = -√3 - i
z(2) = 2e^[ i·(11π / 6) ] = 2[cos(11π / 6) + i·sin(11π / 6) ] = 2[cos(5π / 6) - i·sin(5π / 6) ] = √3 - i

WolframAlpha Kontrolu: http://www.wolframalpha.com/input/?i=cubic roots of (-8i)